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Question: TWO THEIFS HAD ROBED GOLD COINS IN ONE HOUSE...! THEY WANT 2 SHARE EQUALLY...! BUT ONE WAS LEFT...! SO THEY ADDED ANOTHER PERSON NOW 3 SHARED AGAIN ONE COIN WAS REMAINING...! 4,5,6..! AT LAST 7MEMBERS SHARED EQUALLY...! THAT MEANS HOW MANY COINS THEY ROBBED...?;-)
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By swankmuffin
Question: 3 men walk into a hotel. The room they want it is 30 dollars. They each pay ten. Once they get up to their room the manager realizes that the room was only supposed to be 25 dollars. He sends the bellboy up with 5 1 dollar bills. On the way to their room, the belly boy thinks "I can't split five 1s between five guys". So, he pockets 2 of the dollars and gives each of the men a dollar. Now, the men have only paid 9 dollars each. 9X3=27 and the bellboy pocketed 2 dollars which makes 29... Where is the other dollar?
9.7k views
22 ratings
1 saves
By Kaio
Question: Two simple warriors: a vegetable and none. It depends on whether they work together to reduce infinity to one.
9.3k views
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By RiddleWizard
Question: Bobby's teacher gave him a math quiz. Every time he got an answer right, points would be taken away, so whoever had the most points, got the most questions wrong. Bobby's score was the highest, yet he still got the most questions correct out of the class. How is this possible?
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