Logic Riddles

 
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Question: You have an 8 by 8 chess board that has two corner squares diagonal from each other removed. Is there any way to place 31 dominoes of size 2x1 to cover the remaining 62 spaces?

Answer: No. When you remove the two diagonal spaces from the chess board they are both black or both white, making it so that there are two more of the other color. Each domino would cover 1 black and 1 white space. So 31 of them would have to cover 31 white spaces and 31 black spaces but with the corners removed there are 30 of one color and 32 of the other.

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Question: After looking for his long lost brother that he has never met before, Justin is able to learn his brother's home address and name. When he shows up at his house he finds a fireman, a police man, and a mechanic watching television. He immediately hugs his brother.

How does he know which one is his brother?

Hint: How would he know all of their professions?

Answer: Police, firemen, and mechanics all wear name tags. Another acceptable answer would be that two of them were women.

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Question: There are 3 switches downstairs, each corresponding to one of the light bulbs upstairs. How can you figure out which light switch goes to which light bulb by only making 1 trip upstairs?

Answer: You turn on one light bulb. Leave it on for a while. Then, turn that one off and turn another one on. Go upstairs. One light bulb will be cold, one will be warm, and one will be on.

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Question: A Florida man is running down a hall with a piece of paper. The lights flicker and he falls to the ground in tears.

What happened?

Answer: He was delivering a pardon for the man about to get the electric chair but it was too late.

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Question: You have a flashlight that takes 2 working batteries. You have 8 batteries but only 4 of them work.

What is the fewest number of pairs you need to test to guarantee you can get the flashlight on?

Answer: 7. If you break the batteries into 3 groups: Two groups of 3 and one group of 2. By doing this you guarantee that one of the groups has 2 working batteries. Both of the groups of 3 have 3 possible combinations of 2 batteries and the group of 2 only has 1 combination. So, 3 + 3 + 1 = 7 tries at most to find two working batteries.

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